Let the sum be Rs p, rate be r% per annum.
`3p = p(1+r/100)^(3) rArr (1+r/100)=3^(1//3)`
Now, `9p = p(1+r/100)^(n) rArr (1+r/100)^(n)=9`
`3^(n/3) = 3^(2) rArr n/3 rArr n=6`.
`therefore` In 6 years, the sum becomes 9 times itself.
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Solution
The correct option is A
24 years
P(1+R100)12=3P
⇒(1+R100)15=3PP = 3……(i)
Let P(1+R100)n=9P
⇒(1+R100)n=9
⇒(1+R100)n =32
⇒(1+R100)n = {(1+R100)12}2 {using(i)}
⇒(1+R100)n = (1+R100)24
⇒ n = 24
Thus, the required time = 24 years.
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How many years will a sum become 27 times when it trebles itself in 2 years at CI?
So the answer is 6 years.
At what rate per cent will the compound interest does a sum of money become 27 times in 3 years?
The rate of interest per annum is 200 %.
What rate compounded annually will triple a sum in 4 years?
R=12. 5%
What is the rate of interest if a sum of money triples itself in 16 years?
⇒R=162×100=12. 5%