- Anshusonalika
- 4 years ago
- Matematika
At what rate percent per annum will₹4000 amount to₹4410 in2 years when compounded annually?
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- Bhavyamishra
- 4 years ago
- Report
Intrest =amount-principle
=4410-4000
=410
SI=(p×r×t)÷100
410=(4000×r×2)÷100
410×100=8000×r
41000÷8000=r
5•125=r
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अतिथि के रूप में पोस्ट करें
Name
ईमेल
Answer:
Answer:
5%
Step-by-step explanation:
Principal P = Rs.4000
Time(t) = 2 years
Amount A = Rs. 4410
Rate of interest = ?
No. of compound per year n = 1
Formula of Amount of compound interest :
A=P(1+\frac{r}{n})^{nt}A=P(1+
n
r
)
nt
where r is in decimals
Substitute the values
4410=4000(1+r)^{2}4410=4000(1+r)
2
\frac{4410}{4000}=(1+r)^{2}
4000
4410
=(1+r)
2
\sqrt{1.1025}=(1+r)
1.1025
=(1+r)
1.05=(1+r)1.05=(1+r)
0.05=r0.05=r
So, rate of interest = 0.05*100= 5%
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At what rate percent per annum will a sum of Rs. 4000 yield compound interest of Rs. 410 in 2 years?
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Solution
Principal (P) = Rs. 4000
C.I = Rs. 410
∴
Amount (A) = Rs. 4000 + 410 = Rs. 4410
Let rate =R% p.a.
Period (n) = 2 years.
∴ Amount
=P(1+R100)n
⇒AP=(1+R100)2
⇒Rs.44104000=(1+R100)n
⇒4414000=[1+R100]2
⇒(2120)2=(1+R100)2
Comparing, we get
1+R100=2120=1+120
∴R100=120⇒R=10020=5
∴ Rate =5% p.a
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