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Sum
In what time will Rs 15625 amount to Rs 17576 at 4% p.a. compound interest?
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Solution
Here P = Rs.15625, A = 17576, r = 4%
Now, `"P"(1 + "r"/100)^"t"` = A
⇒ `15625(1 + 4/100)^"t"`
= 17576
⇒ `(26/25)^"t"`
= `(17576)/(15625)`
= `(26/25)^3`
By comparing powers, t = 3
Hence time is 3 years.
Concept: Concept of Compound Interest - When the Time is Not an Exact Number of Years and the Interest is Compounded Yearly
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Chapter 3: Compound Interest - Exercise 3.2
Q 8Q 7Q 9
APPEARS IN
Frank Class 9 Maths ICSE
Chapter 3 Compound Interest
Exercise 3.2 | Q 8
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It is given that
Amount = ₹ 2500
Principal = ₹ 2304
Period (n) = 2 years
Consider r% p.a. as the rate of interest
We know that
\begin{aligned} &\mathrm{A}=\mathrm{P}(1+\mathrm{r} / 100)^{\mathrm{n}}\\ &\text { It can be written as }\\ &(1+\mathrm{r} / 100)^{\mathrm{n}}=\mathrm{A} / \mathrm{P} \end{aligned}
Substituting the values
\begin{aligned} &(1+\mathrm{r} / 100)^{2}=2500 / 2304\\ &\text { By further calculation }\\ &(1+\mathrm{r} / 100)^{2}=625 / 576=(25 / 24)^{2} \end{aligned}
So we get
1 + r/100 = 25/24
r/100 = 25/24 – 1
Taking LCM
r = 100/24 = 25/6 = 4 1/6
Hence, the rate of interest is 4 1/6% p.a.
If a sum is compounded annually and becomes 676/625 times itself in 2 years, then find the rate of interest.
- 8%
- 10%
- 5%
- 4%
Answer (Detailed Solution Below)
Option 4 : 4%
Free
20 Questions 20 Marks 15 Mins
Given:
Time = 2 years
The sum becomes 676/625 itself.
Formula used:
A = P(1 + r/100)n
Where, A = Amount, P = Principal, r = Rate of interest, n = Time in years
Calculation:
Let the principal be P.
Amount will become 676P/625 in 2 years
676P/625 = P(1 + r/100)2
⇒ 676/625 = (1 + r/100)2
⇒ (26/25)2 = (1 + r/100)2
⇒ 26/25 = 1 + r/100
⇒ r/100 = 26/25 - 1
⇒ r/100 = 1/25
⇒ r = 4%
∴ The rate of interest is 4%.
Ratio of amount and principal for 2 years if the sum is compounded annually = √A ∶ √P
⇒ √676 ∶ √625
⇒ 26 ∶ 25
Rate of interest = [(26 - 25)/25] × 100
⇒ Rate of interest = (1/25) × 100
⇒ Rate of interest = 4%
∴ Rate of the interest is 4%.
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