The compound interest on a sum of Rs. 64000 at 5% per annum for a certain period is Rs. 4921, while the interest is compounded half-yearly. What will be the compound interest on the same sum at the same rate for the same period, if the interest is compounded annually?
- Rs. 4890
- Rs. 4880
- Rs. 4820
- Rs. 4860
Answer (Detailed Solution Below)
Option 2 : Rs. 4880
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Given:
Principal = Rs. 64000
Compound Interest = Rs. 4921
Rate = 5%
Concept used:
When the sum is compounded half-yearly, then the rate of interest becomes half and time becomes double.
Formula used:
A = P(1 + R/100)T
C.I = A - P
A = P + C.I
Where, A = Amount, P = Principal, T = Time, C.I = Compound interest and R = rate of interest
Calculation:
A = P + C.I
⇒ A = 64000 + 4921 = Rs. 68921
According to the question,
Compounded half-yearly,
A = P(1 + R/100)T
⇒ 68921 = 64000[1 + 5/(2 ×100)]2T
⇒ 68921/64000 = (41/40)2n
⇒ (41/40)3 = (41/40)2n
⇒ 2n = 3
⇒ n = 3/2
Annual
Now, compounded annually
P = Rs. 64000 n = 3/2 = \({1\frac{1}{2}}\) years, and r = 5%
A = P(1 + R/100)T
⇒ A = 64000(1 + 5/100)\({1\frac{1}{2}}\)
⇒ A = 64000(1 + 5/100)1 × (1 + 5/100)1/2
⇒ A = 64000 × (1 + 5/100)(1 + 5/2 × 100)
⇒ A = 64000 × 21/20 × 41/40 = Rs. 688,80
C.I = A - P
⇒ C.I = 68880 - 64000 = Rs. 4880
∴ The compound interest is Rs. 4880.
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Solution
The correct option is A 112
years
Here, Principal P = Rs. 64000, Amount A = Rs 68921, rate
R=5% per annum.
Since the interest is compounded half - yearly.
∴A=P(1+R200)2n
⇒68921=64000(1+5200)2n
⇒6892164000=(4140)2n
⇒(4140)3=(4140)2n
Since the base are same, equating the powers we get
⇒3=2n
⇒n=32
years=112years