Find the compound interest on Rs 12600 for 2 years 4 months at 10% per annum compounded yearly

P = Rs.12,600; R = 10%; n = 2 years

A = P\([1\,+\,\frac R{100}]^n\)  =  12600 \([1\,+\,\frac {10}{100}]^2\) = 12600\([1\,+\,\frac 1{10}]^2\)

= 12600 x \(\frac{11}{10}\) x \(\frac{11}{10}\) = 126 x 121

A = Rs.15246

∴ Compound Interest = Amount – Principal 

= 15,246 – 12,600 

∴ C.I. = Rs.2646 /-

Find compound interest on Rs 12600 for 2 years at 10% p.a. compounded annually.

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    Here, we shall calculate the amount for 2 years using the CI formula. Then this amount will become the principal for next 4 months, i.e. 4/12 years.

    Find the compound interest on Rs 12600 for 2 years 4 months at 10% per annum compounded yearly

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    Sum

    Find CI on Rs. 12600 for 2 years at 10% per annum compounded annually.

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    Solution

    We have,

    A = P`(1 + R/100)^n`, where Principal (P) = ₹ 12600, Rate (R) = 10, Number of years (n) = 2

    = ₹ 12600`(1 + 10/100)^2`

    = ₹ 12600`(11/10)^2`

    = ₹ `12600 xx 11/10 xx 11/10`

    = ₹ 15246.

    CI = A - P

    = ₹ 15246 - ₹ 12600 

    = ₹ 2646.

    Concept: Deducing a Formula for Compound Interest

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    History of Indian Constitution

    15 Questions 15 Marks 9 Mins

    Given:

    The principle = 12600

    The rate = 10% per annum

    The time = 2 years

    Formula used:

    Compound interest = \(P\ \times [{(1\ +\ {R\over 100})}^T -\ 1]\)  (Where P = Principle, R = The rate and T = Time)

    Calculation:

    Let us assume CI is the compound interest 

    ⇒  \(CI\ =\ 12600\ \times [{(1\ +\ {10\over 100})}^2 -\ 1]\)

    ⇒ \(CI\ =\ 12600\ \times [{({110\over 100})}^2 -\ 1]\)

    ⇒ \(CI\ =\ 12600\ \times [{( {1.21})} -\ 1]\)

    ⇒ \(CI\ =\ 12600\ \times 0.21\)

    ⇒ 2646

    ∴ The required result will be 2646.

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    Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

    What is the compound interest on a sum of 12600?

    ∴ The compound interest incurred is Rs. 4171.

    How do I calculate my CI for 2 years?

    Given:.
    Formula Used:.
    C.I = P[{1 + (R/100)}T - 1].
    Calculation:.
    C.I = 5000[{1 + (20/100)}2 - 1].
    ⇒ 5000[{1 + (1/5)}2 - 1].
    ⇒ 5000[(6/5)2 - 1].
    ∴ The compound interest is Rs. 2200..

    What is the difference between the compound interest on Rs 5000 for 1.5 years at 4?

    5000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly? = Rs. 5304.

    What is compound interest per annum?

    Correct Option: D. ⇒ R = 6% per annum.